A 0.50kg disk spins at 250rpm.A torque of 12.5Nm is applied for 0.150s to bring it to rest.What is the disk's radius?
A) 0.54m
B) 0.38m
C) 0.29m
D) 0.14m

Question

Quizplus · Accepted Answer

The correct answer is A because the disk's radius can be calculated using the formula: r = sqrt(2T / (m * a)), where r is the radius, T is the torque, m is the mass, and a is the angular acceleration. Plugging in the given values, we get: r = sqrt(2 * 12.5 Nm / (0.50 kg * (250 rpm * 2 * pi / 60 s)^2)) = 0.54 m.

A 050kg Disk Spins at 250rpm